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Atomic Structure
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Q.1
WBCS Prelims 2023
The ion of an element has three positive charge. Mass number of the atom is 27, and the number of neutrons is 14, What is the number of electrons in the ion?
A. 13
B. 10
C. 14
D. 16
Explanation
Core Formula/Logic: Atomic number = Mass number - Neutrons; Electrons in ion = Atomic number - Charge
Step-by-Step Solution: 1. Calculate atomic number: 27 - 14 = 13.
2. The ion has +3 charge, meaning it lost 3 electrons.
3. Electrons in ion = 13 - 3 = 10.
Common Pitfall: Using atomic number directly without subtracting charge gives 13 (option A). Adding neutrons instead gives 14 (option C). Adding charge to atomic number gives 16 (option D).
Shortcut/Takeaway: For positive ions: Electrons = (Mass number - Neutrons) - Charge. For negative ions: Electrons = (Mass number - Neutrons) + Charge.
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Q.2
WBCS Prelims 2023
If number of molecules present in 9g of water is n, then number of molecules present in 44g of carbon-di-oxide is
A. n
B. 2n
C. n/2
D. 3n
Explanation
Core Formula/Logic: Number of molecules = (Mass/Molar mass) × Avogadro's number; Equal moles contain equal molecules.
Step-by-Step Solution: 1. Molar mass of H2O = 18 g/mol. Moles in 9g = 9/18 = 0.5 mol.
2. Molar mass of CO2 = 44 g/mol. Moles in 44g = 44/44 = 1 mol.
3. Molecules ratio = Moles ratio = 1/0.5 = 2.
4. If 9g H2O has n molecules, then 44g CO2 has 2n molecules.
Common Pitfall: Forgetting molar mass difference gives n (option A). Incorrectly inverting ratio gives n/2 (option C). Multiplying by 3 gives 3n (option D).
Shortcut/Takeaway: Compare moles directly: (44/44) ÷ (9/18) = 1 ÷ 0.5 = 2. So CO2 has twice the molecules, making it 2n.
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Q.3
WBCS Prelims 2015
Mg2+ is isoelectronic with
A. Ca2+
B. Na+
C. Zn2+
D. Cu+
Explanation
Core Formula/Logic: Isoelectronic species have identical electron counts. Mg2+ loses 2 electrons from atomic Mg (12 electrons), leaving 10 electrons.
Step-by-Step Solution: 1. Mg atomic number = 12, so neutral Mg has 12 electrons.
2. Mg2+ loses 2 electrons: 12 - 2 = 10 electrons.
3. Na atomic number = 11, neutral Na has 11 electrons.
4. Na+ loses 1 electron: 11 - 1 = 10 electrons.
5. Ca2+ has 18 electrons (20 - 2), Zn2+ has 28 electrons (30 - 2), Cu+ has 28 electrons (29 - 1).
Common Pitfall: Confusing atomic numbers with electron counts produces Ca2+ (18 electrons). Forgetting to account for charge changes yields Zn2+ or Cu+ with 28 electrons.
Shortcut/Takeaway: For isoelectronic problems, subtract the positive charge from the atomic number to get electron count. Match species with identical results.
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Q.4
WBCS Prelims 2014
The number of electrons present in H+ is
A. Zero
B. One
C. Two
D. Three
Explanation
Why Correct: H+ is a hydrogen ion formed by removing the single electron from a neutral hydrogen atom, leaving a bare proton with zero electrons.
Distractor Analysis: One electron exists in a neutral hydrogen atom (H). Two electrons fill the first electron shell in helium. Three electrons characterize lithium.
Takeaway: Cations (positive ions) always have fewer electrons than their neutral atoms, with the charge indicating the number of electrons lost.
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Q.5
WBCS Prelims 2012
Calculate the shielding suffered by valence electrons in fluorine
A. 5.20
B. 4.80
C. 5.80
D. 4.85
Explanation
Why Correct: Fluorine's valence electrons experience 4.80 shielding according to Slater's rules, which calculate effective nuclear charge by subtracting shielding constant from atomic number.
Distractor Analysis: 5.20 approximates shielding for some heavier halogens, 5.80 represents miscalculations using full core electron counts, and 4.85 results from rounding errors in Slater's rule application.
Takeaway: Slater's rules assign shielding values of 0.35 for electrons in the same group (except 0.30 for 1s), 0.85 for electrons one shell lower, and 1.00 for all inner shells.
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Q.6
WBCS Prelims 2007
Neutron was discovered by
A. J. Chadwick
B. J.J Thomson
C. Rutherford
D. Neil Bohr
Explanation
Why Correct: James Chadwick discovered the neutron in 1932 through experiments bombarding beryllium with alpha particles and observing uncharged radiation.
Distractor Analysis: J.J. Thomson discovered the electron in 1897 using cathode ray tube experiments. Ernest Rutherford discovered the atomic nucleus in 1911 through gold foil scattering experiments. Niels Bohr developed the quantum model of the atom in 1913 with quantized electron orbits.
Takeaway: Chadwick's neutron discovery explained atomic mass discrepancies and earned him the 1935 Nobel Prize in Physics.
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Q.7
WBCS Prelims 2006
Hydrogen peroxide has the same number of electrons as
A. HCHO
B. CH3OH (Methanol)
C. CH2 = CH2
D. CH2CHO
Explanation
Core Formula/Logic: Total electrons = sum of atomic numbers of all atoms. Hydrogen peroxide (H2O2) has 2H (1 each) + 2O (8 each) = 2 + 16 = 18 electrons.
Step-by-Step Solution: 1. H2O2: H atomic number 1 × 2 = 2 electrons, O atomic number 8 × 2 = 16 electrons, total = 18 electrons.
2. HCHO (formaldehyde): H=1, C=6, H=1, O=8 → 1+6+1+8 = 16 electrons.
3. CH3OH: C=6, H=1×4, O=8 → 6+4+8 = 18 electrons.
4. CH2=CH2 (ethene): C=6×2, H=1×4 → 12+4 = 16 electrons.
5. CH2CHO (acetaldehyde fragment): C=6×2, H=1×3, O=8 → 12+3+8 = 23 electrons.
Common Pitfall: Counting only valence electrons instead of total electrons gives wrong totals; forgetting hydrogen atoms in methanol gives 14 electrons.
Shortcut/Takeaway: For neutral molecules, total electrons = sum of atomic numbers; memorize common molecules: H2O=10, NH3=10, CH4=10, CO2=22, C2H5OH=26.
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Q.8
WBCS Prelims 2004
When a helium atom loses an electron, it is converted to a
A. Proton
B. L-particle
C. Deuteron
D. Helium ion
Explanation
Why Correct: A helium atom losing one electron becomes He+, a positively charged helium ion (helium cation).
Distractor Analysis: A proton is specifically the hydrogen-1 nucleus (H+). L-particle is not a recognized particle in standard physics. A deuteron is the nucleus of deuterium, the hydrogen-2 isotope.
Takeaway: Helium losing both electrons becomes He2+, identical to an alpha particle (helium-4 nucleus).
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Q.9
WBCS Prelims 2001
Particles that can be added to the nucleus of an atom without changing chemical properties are called
A. neutron
B. proton
C. electron
D. αparticle
Explanation
Why Correct: Adding neutrons to the nucleus creates isotopes, which have identical chemical properties but different atomic masses.
Distractor Analysis: Adding protons changes the atomic number, creating a different element with distinct chemical properties. Adding electrons affects the atom's charge but not the nucleus; chemical properties depend on electron configuration which is tied to proton number. Alpha particles consist of 2 protons and 2 neutrons, changing both atomic number and mass when added.
Takeaway: Isotopes of an element have the same number of protons but different numbers of neutrons, explaining identical chemical behavior but varying physical properties like radioactivity.
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Q.10
WBCS Prelims 2001
The energy of an electron in the first Bohr orbit is -13.6 eV. What will be its energy in the second Bohr orbit?
A. -6.8eV
B. -3.4eV
C. -27.2eV
D. -13.6eV
Explanation
Core Formula/Logic: In the Bohr model, electron energy in the nth orbit is En = -13.6/n2 eV for hydrogen.
Step-by-Step Solution: 1. For first orbit (n=1): E1 = -13.6/12 = -13.6 eV (given).
2. For second orbit (n=2): E2 = -13.6/22 = -13.6/4 = -3.4 eV.
Common Pitfall: Dividing -13.6 by 2 instead of 4 gives -6.8 eV (option A). Multiplying -13.6 by 2 gives -27.2 eV (option C). Forgetting the n2 dependence gives -13.6 eV (option D).
Shortcut/Takeaway: Energy levels scale inversely with n2: E2 = E1/4 = -13.6/4 = -3.4 eV. Memorize that each higher orbit has less negative (higher) energy.
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Q.11
WBCS Prelims 2000
In 1775 a scientist experimentally showed that air consists of two gases. The name of the scientist is
A. Priestley
B. Laboisier
C. Darwin
D. Davy
Explanation
Why Correct: Joseph Priestley isolated oxygen in 1774 and demonstrated air contains at least two distinct gases through mercury and nitric oxide experiments.
Distractor Analysis: Antoine Lavoisier named oxygen and developed the combustion theory but worked after Priestley's discovery. Charles Darwin proposed biological evolution through natural selection. Humphry Davy discovered several alkali and alkaline earth metals through electrolysis.
Takeaway: Priestley called his discovered gas "dephlogisticated air" while Lavoisier renamed it "oxygen" and correctly identified its role in combustion and respiration.
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