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Gravitation
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Q.1
WBCS Prelims 2015
When a ball is taken from the equator to the pole of the earth
A. Its mass increases
B. Both its mass and weight change
C. Its weight increases
D. Its weight decreases
Explanation
Why Correct: Weight depends on gravitational acceleration (g), which increases from equator (≈9.78 m/s²) to pole (≈9.83 m/s²) due to Earth's oblate shape and centrifugal force, so weight increases while mass remains constant.
Distractor Analysis: Mass is the amount of matter and does not change with location. Weight decreases at the equator because g is lower there, not at the pole. Both mass and weight changing is incorrect because mass stays the same.
Takeaway: g is maximum at poles and minimum at the equator, with a difference of about 0.05 m/s². Weight = mass × g, so weight variation follows g's variation.
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Q.2
WBCS Prelims 2009
The weight of an object is
A. Maximum at the centre of the earth
B. Maximum at infinity
C. Maximum at the surface of the earth
D. Same everywhere from the center of the earth to infinity
Explanation
Why Correct: Weight W = mg, where g is acceleration due to gravity. Gravity g reaches its maximum value at Earth's surface (approximately 9.8 m/s2), decreasing both above (with altitude) and below (inside Earth).
Distractor Analysis: At Earth's center, gravitational forces from all directions cancel, making weight zero. At infinity, gravitational force approaches zero, so weight approaches zero. Weight varies with location due to changes in g.
Takeaway: Inside Earth, g decreases linearly with distance from center, reaching zero at the center. Outside Earth, g decreases with inverse square law: g ∝ 1/r2.
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Q.3
WBCS Prelims 2008
The weight of a body on the surface of the earth is 10 kg. Its weight at the center of the earth is
A. 0 kg
B. 5 kg
C. 10 kg
D. Infinite
Explanation
Core Formula/Logic: Weight = mass × gravitational acceleration (g). At Earth's center, gravitational acceleration becomes zero because mass pulls equally in all directions.
Step-by-Step Solution: 1. Weight depends on gravitational force: W = m × g. 2. At Earth's center, the net gravitational force is zero (g = 0). 3. Therefore, W = m × 0 = 0.
Common Pitfall: Confusing weight with mass produces 10 kg. Assuming halved gravity gives 5 kg. Thinking gravitational force becomes infinite at the center yields Infinite.
Shortcut/Takeaway: Weight is zero at Earth's center regardless of surface weight. Mass remains constant, but gravitational acceleration cancels out completely.
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Q.4
WBCS Prelims 2007
When a body is raised upwards from the surface of the earth, its weight shall
A. Increase
B. Remain same
C. Decrease
D. Fluctuate
Explanation
Why Correct: Weight equals gravitational force, which follows Newton's law of universal gravitation: F = G * (m1 * m2) / r^2. As distance r from Earth's center increases, gravitational force decreases.
Distractor Analysis: Increase would occur only if gravitational force strengthened with distance, which contradicts physics. Remain same would require gravitational force to be independent of distance, which only holds for uniform gravitational fields. Fluctuate suggests periodic or irregular changes, but weight decreases monotonically with altitude.
Takeaway: Weight becomes zero at infinite distance from Earth, but apparent weightlessness occurs in free-fall orbits where gravitational force still exists but is balanced by centripetal acceleration.
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Q.5
WBCS Prelims 2006
The value of acceleration due to gravity at higher altitudes
A. Decreases
B. Increases
C. Remains constant
D. None of the above
Explanation
Why Correct: Acceleration due to gravity decreases with altitude because gravitational force follows Newton's inverse square law: g = GM/r2, where r is distance from Earth's center.
Distractor Analysis: Increases contradicts the inverse square relationship where gravity weakens with distance. Remains constant only approximates small altitude changes near Earth's surface where variation is negligible. None of the above is incorrect since the established physical law confirms the decrease.
Takeaway: At Earth's surface, g ≈ 9.8 m/s2; at altitude equal to Earth's radius (6371 km), g reduces to about 2.45 m/s2.
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Q.6
WBCS Prelims 2004
The period of rotation of an artificial earth satellite
A. depends on its distance from the earth’s surface
B. is proportional to its distance from the earth’s centre
C. is inversely proportional to its mass
D. 24 hours
Explanation
Why Correct: Kepler's third law for circular orbits gives T = 2π√(r³/GM), where r is distance from Earth's center, so period depends on orbital radius.
Distractor Analysis: is proportional to its distance from the earth’s centre is incorrect—period is proportional to r^(3/2), not r. is inversely proportional to its mass is wrong—satellite mass cancels in orbital equations. 24 hours applies only to geostationary satellites at specific altitude.
Takeaway: Geostationary satellites orbit at ~35,786 km altitude with 24-hour period, matching Earth's rotation for fixed positioning.
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Q.7
WBCS Prelims 2004
A rocket leaves the earth, lands on the moon and returns to earth. It will require the maximum energy to
A. rise from the earth
B. land on the moon
C. rise from the moon
D. land on the earth
Explanation
Why Correct: Earth's gravitational acceleration (9.8 m/s2) is about six times stronger than the moon's (1.6 m/s2), so escaping Earth's gravity requires the most energy.
Distractor Analysis: Landing on the moon uses energy for braking but benefits from the moon's weaker gravity. Rising from the moon requires escaping its much weaker gravitational field. Landing on Earth uses atmospheric drag and parachutes, converting kinetic energy to heat rather than requiring propulsive energy.
Takeaway: The energy required to escape a celestial body depends on its escape velocity, which equals sqrt(2GM/r) where G is the gravitational constant, M is the mass, and r is the radius.
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Q.8
WBCS Prelims 2003
133. Which one of the following is the weakest force?
A. Gravitational Force
B. Electromagnetic force
C. Nuclear force
D. Electrostatic force
Explanation
Why Correct: Gravitational force is the weakest fundamental force, with a relative strength of about 10^-39 compared to the strong nuclear force.
Distractor Analysis: Electromagnetic force governs interactions between charged particles and is 10^36 times stronger than gravity. Nuclear force binds protons and neutrons in atomic nuclei and is the strongest fundamental force. Electrostatic force is a manifestation of electromagnetic force between stationary charges.
Takeaway: The four fundamental forces from weakest to strongest are: gravitational, weak nuclear, electromagnetic, and strong nuclear.
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Q.9
WBCS Prelims 2000
The weight of an iron ball on earth is 12 Kg. Its weight on moon will be
A. 18kg.
B. 9 kg.
C. 12 kg.
D. 2 kg.
Explanation
Core Formula/Logic: Weight = mass × gravitational acceleration (W = m×g). Moon's gravity is approximately 1/6th of Earth's gravity (g_moon ≈ g_earth/6 ≈ 1.63 m/s2).
Step-by-Step Solution: 1. Mass remains constant everywhere: m = 12 kg.
2. Weight on Earth: W_earth = 12 kg × g_earth.
3. Weight on Moon: W_moon = 12 kg × (g_earth/6) = (12 kg × g_earth)/6 = W_earth/6.
4. Since W_earth = 12 kg-weight (not mass), W_moon = 12/6 = 2 kg-weight.
Common Pitfall: Confusing mass (constant) with weight (varies with gravity) leads to selecting 12 kg. Thinking gravity differences are smaller (like 3/4) produces 9 kg. Multiplying instead of dividing gives 18 kg.
Shortcut/Takeaway: Moon weight = Earth weight ÷ 6. Always divide Earth weight by 6 for lunar weight calculations.
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